解:∵點(diǎn)D為AC中點(diǎn),
∴DC=

AC,
∵點(diǎn)E為BC中點(diǎn),
∴CE=

CB,
∴DE=DC+CE=

AC+

BC=

AB;
(1)當(dāng)線段AB=4cm時(shí),DE=

×4cm=2cm;
(2)線段AB=6cm時(shí),DE=

6cm=3cm;
(3)線段AB=acm時(shí),DE=

acm.
分析:根據(jù)點(diǎn)D為AC中點(diǎn)可得DC=

AC,再由點(diǎn)E為BC中點(diǎn)可得CE=

CB,進(jìn)而得到DE=DC+CE=

AC+

BC=

AB,再把AB的長(zhǎng)代入即可得到答案.
點(diǎn)評(píng):此題主要考查了計(jì)算線段的長(zhǎng),關(guān)鍵是掌握線段的中點(diǎn)把線段分成相等的兩部分.