【答案】
分析:把函數(shù)
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可看作由函數(shù)y=log
at與t=
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復(fù)合而成的,根據(jù)復(fù)合函數(shù)單調(diào)性的判斷方法:“同增異減,逐個(gè)判斷即可.
解答:解:
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可看作由函數(shù)y=log
at與t=
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復(fù)合而成的,
(1)中,當(dāng)0<a<1時(shí),y=log
at單調(diào)遞減,x∈(-∞,0)時(shí),t=
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單調(diào)遞增,所以
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單調(diào)遞減,故(1)滿足要求;
(2)中,當(dāng)0<a<1時(shí),y=log
at單調(diào)遞減,x∈(0,+∞)時(shí),t=
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單調(diào)遞減,所以
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單調(diào)遞增,故(2)不滿足要求;
(3)中,當(dāng)a>1時(shí),y=log
at單調(diào)遞增,x∈(-∞,0)時(shí),t=
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單調(diào)遞增,所以
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單調(diào)遞增,故(3)不滿足要求;
(4)中,當(dāng)a>1時(shí),y=log
at單調(diào)遞增,x∈(0,+∞)時(shí),t=
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單調(diào)遞減,所以
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單調(diào)遞減,故(4)滿足要求;
故答案為:(1)(4).
點(diǎn)評(píng):本題考查復(fù)合函數(shù)單調(diào)性的判斷方法,若原函數(shù)可分解為兩個(gè)簡(jiǎn)單函數(shù),則根據(jù)“同增異減”即可判斷其單調(diào)性.