【答案】
分析:先求出

的坐標(biāo),
(1)利用向量垂直的充要條件:數(shù)量積為0,列出方程求出k.
(2)利用向量共線的坐標(biāo)形式的充要條件:坐標(biāo)交叉相乘相等,列出方程求出k,將k代入兩向量的坐標(biāo),判斷出方向相反.
解答:解:k


=(1,2)-3(-3,2)=(10,-4)
(1)


,得


=10(k-3)-4(2k+2)=2k-38=0,k=19
(2)


,得-4(k-3)=10(2k+2),k=-

此時(shí)k

(10,-4),所以方向相反.
點(diǎn)評:本題考查向量的坐標(biāo)運(yùn)算、向量垂直的充要條件、向量的坐標(biāo)形式的數(shù)量積公式、向量共線的坐標(biāo)形式的充要條件.