9.函數(shù)的定義域?yàn)镽.且.已知.那么當(dāng)?shù)倪f增區(qū)間是 查看更多

 

題目列表(包括答案和解析)

函數(shù)的定義域?yàn)镽,且,已知為奇函數(shù),當(dāng)時(shí),,那么當(dāng)時(shí), 的遞減區(qū)間是                                                             

A.            B.               C.           D.

查看答案和解析>>

4、已知函數(shù)f(x)=3x,那么函數(shù)f(x)的反函數(shù)f-1(x)的定義域?yàn)椋ā 。?/div>

查看答案和解析>>

已知函數(shù)f(x)是定義域?yàn)镽的偶函數(shù),且f(x+1)=
1
f(x)
,若f(x)在[-1,0]上是減函數(shù),那么f(x)在[2,3]上是( 。
A、增函數(shù)
B、減函數(shù)
C、先增后減得函數(shù)
D、先減后增的函數(shù)

查看答案和解析>>

已知函數(shù)f(x)是定義域?yàn)镽的偶函數(shù),且f(x+1)=-f(x),若f(x)在[-1,0]上是減函數(shù),那么f(x)在[1,3]上是( 。

查看答案和解析>>

已知奇函數(shù)f(x)的定義域?yàn)镽,且對(duì)于任意實(shí)數(shù)x都有f(x+4)=f(x)成立,又f(1)=4,那么f[f( 7)]等于( 。

查看答案和解析>>

一.選擇題

1―5  CBABA   6―10  CADDA

二.填空題

11.       12.()       13.2          14.         15.

16.(1,4)

三.解答題

數(shù)學(xué)理數(shù)學(xué)理17,解:①         =2(1,0)                      (2分)             

        ?,                                        (4分)

?

        cos              =

 

        由,  ,    即B=              (6分)

                                               (7分)

                                                        (9分)

,                                                         (11分)

的取值范圍是(,1                                                      (13分)

18.解:①設(shè)雙曲線方程為:  ()                                 (1分)

由橢圓,求得兩焦點(diǎn),                                           (3分)

,又為一條漸近線

, 解得:                                                     (5分)

                                                    (6分)

②設(shè),則                                                      (7分)

      

?                             (9分)

,  ?              (10分)

                                                (11分)

  ?

?                                        (13分)

              單減區(qū)間為[]        (6分)

             

            ②(i)當(dāng)                                                      (8分)

            (ii)當(dāng)

            ,  (),,

            則有                                                                     (10分)

                                                           (11分)

              在(0,1]上單調(diào)遞減                     (12分)

                                                             (13分)

            20.解:①       

                                                                    (2分)

            從而數(shù)列{}是首項(xiàng)為1,公差為C的等差數(shù)列

              即                                (4分)

             

               即………………※              (6分)

            當(dāng)n=1時(shí),由※得:c<0                                                    (7分)

            當(dāng)n=2時(shí),由※得:                                                 (8分)

            當(dāng)n=3時(shí),由※得:                                                 (9分)

            當(dāng)

                (

                                                      (11分)

                                     (12分)

            綜上分析可知,滿足條件的實(shí)數(shù)c不存在.                                    (13分)

            21.解:①設(shè)過(guò)A作拋物線的切線斜率為K,則切線方程:

                                                                            (2分)

                即

                                                                                                               (3分)

            ②設(shè)   又

                 

                                                                     (4分)

            同理可得 

                                                            (5分)

            又兩切點(diǎn)交于 

                                           (6分)

            ③由  可得:

             

                                                            (8分)

                              (9分)

             

            當(dāng) 

            當(dāng) 

                                                                 (11分)

            當(dāng)且僅當(dāng),取 “=”,此時(shí)

                                                   (12分)

            22.①證明:由,    

              即證

              ()                                    (1分)

            當(dāng)  

                  即:                          (3分)

              ()    

            當(dāng)   

               

                                                                     (6分)

            ②由      

            數(shù)列

                                                          (8分)

            由①可知, 

                                (10分)

            由錯(cuò)位相減法得:                                       (11分)

                                                (12分)

             

             


            同步練習(xí)冊(cè)答案