Question

9．$\frac{2\frac{2}{15}+4\frac{2}{3}+3.5}{0.5×（1\frac{1}{20}+4.1）}$+$\frac{19.5+4\frac{1}{2}+3\frac{1}{3}×1.9}{\frac{62}{70}-0.16}$=45$\frac{304}{381}$．

Answer 1

分析 根據(jù)繁分?jǐn)?shù)的化簡方法分別化簡$\frac{2\frac{2}{15}+4\frac{2}{3}+3.5}{0.5×（1\frac{1}{20}+4.1）}$和$\frac{19.5+4\frac{1}{2}+3\frac{1}{3}×1.9}{\frac{62}{70}-0.16}$，再相加即可求解．

解答 解：$\frac{2\frac{2}{15}+4\frac{2}{3}+3.5}{0.5×（1\frac{1}{20}+4.1）}$+$\frac{19.5+4\frac{1}{2}+3\frac{1}{3}×1.9}{\frac{62}{70}-0.16}$
=$\frac{2\frac{2}{15}+4\frac{10}{15}+3.5}{0.5×5.15}$+$\frac{24+\frac{19}{3}}{\frac{127}{175}}$
=$\frac{10.3}{2.575}$+$\frac{\frac{91}{3}}{\frac{127}{175}}$
=4+41$\frac{304}{381}$
=45$\frac{304}{381}$
故答案為：45$\frac{304}{381}$．

點(diǎn)評(píng) 繁分?jǐn)?shù)的定義：如分?jǐn)?shù)形式，分子或分母含有分?jǐn)?shù)，或分子與分母都含有分?jǐn)?shù)的數(shù)，叫繁分?jǐn)?shù)．把繁分?jǐn)?shù)化為最簡分?jǐn)?shù)或整數(shù)的過程，叫做繁分?jǐn)?shù)的化簡．