解:(1)2.5:X=4:1.4,
4x=2.5×1.4,
4x÷4=2.5×1.4÷4,
x=0.875;
(2)
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=
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,
1.5x=0.9×3,
1.5x÷1.5=0.9×3÷1.5,
x=1.8;
(3)
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=
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,
4.5x=2.4×1.75,
4.5÷4.5=2.4×1.75÷4.5,
x=
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;
(4)0.15:18%=6.5:X,
0.15x=18%×6.5,
0.15x÷0.15=18%×6.5÷0.15,
x=7.8;
(5)
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:X=
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:4,
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X=4×
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,
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X
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=4×
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,
X=
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;
(6)0.375:0.05=X:0.6,
0.05x=0.375×0.6,
0.05x÷0.05=0.375×0.6÷0.05,
x=4.5.
分析:(1)根據(jù)比例的基本性質,把原式轉化為4x=2.5×1.4,再根據(jù)等式的性質,在方程兩邊同時除以4求解,
(2)根據(jù)比例的基本性質,把原式轉化為1.5x=0.9×3,再根據(jù)等式的性質,在方程兩邊同時除以1.5求解,
(3)根據(jù)比例的基本性質,把原式轉化為4.5x=1.75×2.4,再根據(jù)等式的性質,在方程兩邊同時除以4.5求解,
(4)根據(jù)比例的基本性質,把原式轉化為0.15x=18%×6.5,再根據(jù)等式的性質,在方程兩邊同時除以0.15求解,
(5)根據(jù)比例的基本性質,把原式轉化為
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x=
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×4,再根據(jù)等式的性質,在方程兩邊同時除以
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求解,
(6)根據(jù)比例的基本性質,把原式轉化為0.05x=0.375×0.6,再根據(jù)等式的性質,在方程兩邊同時除以1.5求解.
點評:本題考查了學生根據(jù)比例的基本性質和等式的性質解方程的能力.