Question

如圖，以A，C，E和C，D，B為頂點(diǎn)的兩個(gè)三角形相似，寫(xiě)出對(duì)應(yīng)邊和對(duì)應(yīng)角．

Answer 1

答案：
解析：

解：因?yàn)橐訟，C，E和C，D，B為頂點(diǎn)的兩個(gè)三角形相似，所以△CAE∽△CDB，對(duì)應(yīng)邊分別為AE對(duì)應(yīng)DB，AC對(duì)應(yīng)DC，CE對(duì)應(yīng)CB，對(duì)應(yīng)角分別為∠C對(duì)應(yīng)∠C，∠AEC對(duì)應(yīng)∠DBC，∠A對(duì)應(yīng)∠D． 　　分析：由已知條件結(jié)合圖形，很明顯，∠C是公共角，而公共角所對(duì)的邊是對(duì)應(yīng)邊，AE的對(duì)應(yīng)邊為DB；AC是△ACE中余下的兩邊中較長(zhǎng)的邊，故AC的對(duì)應(yīng)邊為CD，最后一邊CE對(duì)應(yīng)CB，根據(jù)對(duì)應(yīng)邊所對(duì)的角是對(duì)應(yīng)角得∠C對(duì)應(yīng)∠C，∠AEC對(duì)應(yīng)∠DBC，∠A對(duì)應(yīng)∠D． 　　說(shuō)明：寫(xiě)相似三角形時(shí)，對(duì)應(yīng)頂點(diǎn)應(yīng)順次有序，便于找對(duì)應(yīng)點(diǎn)、對(duì)應(yīng)角、對(duì)應(yīng)邊．